-7(-2u+2)-3u=2(u-6)-5

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Solution for -7(-2u+2)-3u=2(u-6)-5 equation: 



-7(-2u+2)-3u=2(u-6)-5

We move all terms to the left:

-7(-2u+2)-3u-(2(u-6)-5)=0

We add all the numbers together, and all the variables

-3u-7(-2u+2)-(2(u-6)-5)=0

We multiply parentheses

-3u+14u-(2(u-6)-5)-14=0



We calculate terms in parentheses: -(2(u-6)-5), so:

2(u-6)-5

We multiply parentheses

2u-12-5

We add all the numbers together, and all the variables

2u-17

Back to the equation:

-(2u-17)



We add all the numbers together, and all the variables

11u-(2u-17)-14=0

We get rid of parentheses

11u-2u+17-14=0

We add all the numbers together, and all the variables

9u+3=0

We move all terms containing u to the left, all other terms to the right

9u=-3

u=-3/9

u=-1/3

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