-7(-3u+2)-3u=4(u-4)-6

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Solution for -7(-3u+2)-3u=4(u-4)-6 equation: 



-7(-3u+2)-3u=4(u-4)-6

We move all terms to the left:

-7(-3u+2)-3u-(4(u-4)-6)=0

We add all the numbers together, and all the variables

-3u-7(-3u+2)-(4(u-4)-6)=0

We multiply parentheses

-3u+21u-(4(u-4)-6)-14=0



We calculate terms in parentheses: -(4(u-4)-6), so:

4(u-4)-6

We multiply parentheses

4u-16-6

We add all the numbers together, and all the variables

4u-22

Back to the equation:

-(4u-22)



We add all the numbers together, and all the variables

18u-(4u-22)-14=0

We get rid of parentheses

18u-4u+22-14=0

We add all the numbers together, and all the variables

14u+8=0

We move all terms containing u to the left, all other terms to the right

14u=-8

u=-8/14

u=-4/7

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