-7(-3y+1)-y=2(y-7)-5

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Solution for -7(-3y+1)-y=2(y-7)-5 equation: 



-7(-3y+1)-y=2(y-7)-5

We move all terms to the left:

-7(-3y+1)-y-(2(y-7)-5)=0

We add all the numbers together, and all the variables

-1y-7(-3y+1)-(2(y-7)-5)=0

We multiply parentheses

-1y+21y-(2(y-7)-5)-7=0



We calculate terms in parentheses: -(2(y-7)-5), so:

2(y-7)-5

We multiply parentheses

2y-14-5

We add all the numbers together, and all the variables

2y-19

Back to the equation:

-(2y-19)



We add all the numbers together, and all the variables

20y-(2y-19)-7=0

We get rid of parentheses

20y-2y+19-7=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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