-7(-4y+1)-6y=6(y-2)-3

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Solution for -7(-4y+1)-6y=6(y-2)-3 equation: 



-7(-4y+1)-6y=6(y-2)-3

We move all terms to the left:

-7(-4y+1)-6y-(6(y-2)-3)=0

We add all the numbers together, and all the variables

-6y-7(-4y+1)-(6(y-2)-3)=0

We multiply parentheses

-6y+28y-(6(y-2)-3)-7=0



We calculate terms in parentheses: -(6(y-2)-3), so:

6(y-2)-3

We multiply parentheses

6y-12-3

We add all the numbers together, and all the variables

6y-15

Back to the equation:

-(6y-15)



We add all the numbers together, and all the variables

22y-(6y-15)-7=0

We get rid of parentheses

22y-6y+15-7=0

We add all the numbers together, and all the variables

16y+8=0

We move all terms containing y to the left, all other terms to the right

16y=-8

y=-8/16

y=-1/2

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