-7(1+6x)-8x=40-3x

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Solution for -7(1+6x)-8x=40-3x equation:



-7(1+6x)-8x=40-3x
We move all terms to the left:
-7(1+6x)-8x-(40-3x)=0
We add all the numbers together, and all the variables
-7(6x+1)-8x-(-3x+40)=0
We add all the numbers together, and all the variables
-8x-7(6x+1)-(-3x+40)=0
We multiply parentheses
-8x-42x-(-3x+40)-7=0
We get rid of parentheses
-8x-42x+3x-40-7=0
We add all the numbers together, and all the variables
-47x-47=0
We move all terms containing x to the left, all other terms to the right
-47x=47
x=47/-47
x=-1

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