-7(1+b)=6(2b-1)

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Solution for -7(1+b)=6(2b-1) equation: 



-7(1+b)=6(2b-1)

We move all terms to the left:

-7(1+b)-(6(2b-1))=0

We add all the numbers together, and all the variables

-7(b+1)-(6(2b-1))=0

We multiply parentheses

-7b-(6(2b-1))-7=0



We calculate terms in parentheses: -(6(2b-1)), so:

6(2b-1)

We multiply parentheses

12b-6

Back to the equation:

-(12b-6)



We get rid of parentheses

-7b-12b+6-7=0

We add all the numbers together, and all the variables

-19b-1=0

We move all terms containing b to the left, all other terms to the right

-19b=1

b=1/-19

b=-1/19

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