-7(1-3k)+4=-4(k-5)+2k

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Solution for -7(1-3k)+4=-4(k-5)+2k equation: 



-7(1-3k)+4=-4(k-5)+2k

We move all terms to the left:

-7(1-3k)+4-(-4(k-5)+2k)=0

We add all the numbers together, and all the variables

-7(-3k+1)-(-4(k-5)+2k)+4=0

We multiply parentheses

21k-(-4(k-5)+2k)-7+4=0



We calculate terms in parentheses: -(-4(k-5)+2k), so:

-4(k-5)+2k

We add all the numbers together, and all the variables

2k-4(k-5)

We multiply parentheses

2k-4k+20

We add all the numbers together, and all the variables

-2k+20

Back to the equation:

-(-2k+20)



We add all the numbers together, and all the variables

21k-(-2k+20)-3=0

We get rid of parentheses

21k+2k-20-3=0

We add all the numbers together, and all the variables

23k-23=0

We move all terms containing k to the left, all other terms to the right

23k=23

k=23/23

k=1

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