-7(1-9b)-5(12b+4)=1-8b+b+2

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Solution for -7(1-9b)-5(12b+4)=1-8b+b+2 equation: 



-7(1-9b)-5(12b+4)=1-8b+b+2

We move all terms to the left:

-7(1-9b)-5(12b+4)-(1-8b+b+2)=0

We add all the numbers together, and all the variables

-7(-9b+1)-5(12b+4)-(-7b+3)=0

We multiply parentheses

63b-60b-(-7b+3)-7-20=0

We get rid of parentheses

63b-60b+7b-3-7-20=0

We add all the numbers together, and all the variables

10b-30=0

We move all terms containing b to the left, all other terms to the right

10b=30

b=30/10

b=3

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