-7(10+2x)=6-20(x-4)

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Solution for -7(10+2x)=6-20(x-4) equation: 



-7(10+2x)=6-20(x-4)

We move all terms to the left:

-7(10+2x)-(6-20(x-4))=0

We add all the numbers together, and all the variables

-7(2x+10)-(6-20(x-4))=0

We multiply parentheses

-14x-(6-20(x-4))-70=0



We calculate terms in parentheses: -(6-20(x-4)), so:

6-20(x-4)

determiningTheFunctionDomain
-20(x-4)+6

We multiply parentheses

-20x+80+6

We add all the numbers together, and all the variables

-20x+86

Back to the equation:

-(-20x+86)



We get rid of parentheses

-14x+20x-86-70=0

We add all the numbers together, and all the variables

6x-156=0

We move all terms containing x to the left, all other terms to the right

6x=156

x=156/6

x=26

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