-7(2u-3)+3u=7(u+5)

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Solution for -7(2u-3)+3u=7(u+5) equation: 



-7(2u-3)+3u=7(u+5)

We move all terms to the left:

-7(2u-3)+3u-(7(u+5))=0

We add all the numbers together, and all the variables

3u-7(2u-3)-(7(u+5))=0

We multiply parentheses

3u-14u-(7(u+5))+21=0



We calculate terms in parentheses: -(7(u+5)), so:

7(u+5)

We multiply parentheses

7u+35

Back to the equation:

-(7u+35)



We add all the numbers together, and all the variables

-11u-(7u+35)+21=0

We get rid of parentheses

-11u-7u-35+21=0

We add all the numbers together, and all the variables

-18u-14=0

We move all terms containing u to the left, all other terms to the right

-18u=14

u=14/-18

u=-7/9

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