-7(2u-4)+2u=4(u+8)

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Solution for -7(2u-4)+2u=4(u+8) equation: 



-7(2u-4)+2u=4(u+8)

We move all terms to the left:

-7(2u-4)+2u-(4(u+8))=0

We add all the numbers together, and all the variables

2u-7(2u-4)-(4(u+8))=0

We multiply parentheses

2u-14u-(4(u+8))+28=0



We calculate terms in parentheses: -(4(u+8)), so:

4(u+8)

We multiply parentheses

4u+32

Back to the equation:

-(4u+32)



We add all the numbers together, and all the variables

-12u-(4u+32)+28=0

We get rid of parentheses

-12u-4u-32+28=0

We add all the numbers together, and all the variables

-16u-4=0

We move all terms containing u to the left, all other terms to the right

-16u=4

u=4/-16

u=-1/4

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