-7(2y-3)+y=3(y+9)

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Solution for -7(2y-3)+y=3(y+9) equation: 



-7(2y-3)+y=3(y+9)

We move all terms to the left:

-7(2y-3)+y-(3(y+9))=0

We add all the numbers together, and all the variables

y-7(2y-3)-(3(y+9))=0

We multiply parentheses

y-14y-(3(y+9))+21=0



We calculate terms in parentheses: -(3(y+9)), so:

3(y+9)

We multiply parentheses

3y+27

Back to the equation:

-(3y+27)



We add all the numbers together, and all the variables

-13y-(3y+27)+21=0

We get rid of parentheses

-13y-3y-27+21=0

We add all the numbers together, and all the variables

-16y-6=0

We move all terms containing y to the left, all other terms to the right

-16y=6

y=6/-16

y=-3/8

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