-7(2y-6)+3y=7(y+4)

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Solution for -7(2y-6)+3y=7(y+4) equation: 



-7(2y-6)+3y=7(y+4)

We move all terms to the left:

-7(2y-6)+3y-(7(y+4))=0

We add all the numbers together, and all the variables

3y-7(2y-6)-(7(y+4))=0

We multiply parentheses

3y-14y-(7(y+4))+42=0



We calculate terms in parentheses: -(7(y+4)), so:

7(y+4)

We multiply parentheses

7y+28

Back to the equation:

-(7y+28)



We add all the numbers together, and all the variables

-11y-(7y+28)+42=0

We get rid of parentheses

-11y-7y-28+42=0

We add all the numbers together, and all the variables

-18y+14=0

We move all terms containing y to the left, all other terms to the right

-18y=-14

y=-14/-18

y=7/9

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