-7(2z-5)=28+9z

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Solution for -7(2z-5)=28+9z equation:



-7(2z-5)=28+9z
We move all terms to the left:
-7(2z-5)-(28+9z)=0
We add all the numbers together, and all the variables
-7(2z-5)-(9z+28)=0
We multiply parentheses
-14z-(9z+28)+35=0
We get rid of parentheses
-14z-9z-28+35=0
We add all the numbers together, and all the variables
-23z+7=0
We move all terms containing z to the left, all other terms to the right
-23z=-7
z=-7/-23
z=7/23

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