-7(3x+1)(6x-18)=0

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Solution for -7(3x+1)(6x-18)=0 equation:



-7(3x+1)(6x-18)=0
We multiply parentheses ..
-7(+18x^2-54x+6x-18)=0
We multiply parentheses
-126x^2+378x-42x+126=0
We add all the numbers together, and all the variables
-126x^2+336x+126=0
a = -126; b = 336; c = +126;
Δ = b2-4ac
Δ = 3362-4·(-126)·126
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{176400}=420$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-420}{2*-126}=\frac{-756}{-252} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+420}{2*-126}=\frac{84}{-252} =-1/3 $

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