-7(3x-2)=10-21x+4

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Solution for -7(3x-2)=10-21x+4 equation: 



-7(3x-2)=10-21x+4

We move all terms to the left:

-7(3x-2)-(10-21x+4)=0

We add all the numbers together, and all the variables

-7(3x-2)-(-21x+14)=0

We multiply parentheses

-21x-(-21x+14)+14=0

We get rid of parentheses

-21x+21x-14+14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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