-7(3x-3)=40-2x

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Solution for -7(3x-3)=40-2x equation: 



-7(3x-3)=40-2x

We move all terms to the left:

-7(3x-3)-(40-2x)=0

We add all the numbers together, and all the variables

-7(3x-3)-(-2x+40)=0

We multiply parentheses

-21x-(-2x+40)+21=0

We get rid of parentheses

-21x+2x-40+21=0

We add all the numbers together, and all the variables

-19x-19=0

We move all terms containing x to the left, all other terms to the right

-19x=19

x=19/-19

x=-1

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