-7(3x-8)+6(x-3)=7(3x-12)+16x

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Solution for -7(3x-8)+6(x-3)=7(3x-12)+16x equation: 



-7(3x-8)+6(x-3)=7(3x-12)+16x

We move all terms to the left:

-7(3x-8)+6(x-3)-(7(3x-12)+16x)=0

We multiply parentheses

-21x+6x-(7(3x-12)+16x)+56-18=0



We calculate terms in parentheses: -(7(3x-12)+16x), so:

7(3x-12)+16x

We add all the numbers together, and all the variables

16x+7(3x-12)

We multiply parentheses

16x+21x-84

We add all the numbers together, and all the variables

37x-84

Back to the equation:

-(37x-84)



We add all the numbers together, and all the variables

-15x-(37x-84)+38=0

We get rid of parentheses

-15x-37x+84+38=0

We add all the numbers together, and all the variables

-52x+122=0

We move all terms containing x to the left, all other terms to the right

-52x=-122

x=-122/-52

x=2+9/26

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