-7(3y-6)=8y=3(y=8)

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Solution for -7(3y-6)=8y=3(y=8) equation: 



-7(3y-6)=8y=3(y=8)

We move all terms to the left:

-7(3y-6)-(8y)=0

We add all the numbers together, and all the variables

-8y-7(3y-6)=0

We multiply parentheses

-8y-21y+42=0

We add all the numbers together, and all the variables

-29y+42=0

We move all terms containing y to the left, all other terms to the right

-29y=-42

y=-42/-29

y=1+13/29

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