-7(3z+1)+7z=3(z-7)+7z

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Solution for -7(3z+1)+7z=3(z-7)+7z equation: 



-7(3z+1)+7z=3(z-7)+7z

We move all terms to the left:

-7(3z+1)+7z-(3(z-7)+7z)=0

We add all the numbers together, and all the variables

7z-7(3z+1)-(3(z-7)+7z)=0

We multiply parentheses

7z-21z-(3(z-7)+7z)-7=0



We calculate terms in parentheses: -(3(z-7)+7z), so:

3(z-7)+7z

We add all the numbers together, and all the variables

7z+3(z-7)

We multiply parentheses

7z+3z-21

We add all the numbers together, and all the variables

10z-21

Back to the equation:

-(10z-21)



We add all the numbers together, and all the variables

-14z-(10z-21)-7=0

We get rid of parentheses

-14z-10z+21-7=0

We add all the numbers together, and all the variables

-24z+14=0

We move all terms containing z to the left, all other terms to the right

-24z=-14

z=-14/-24

z=7/12

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