-7(3z+5)=-20z-2(-z-8)

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Solution for -7(3z+5)=-20z-2(-z-8) equation: 



-7(3z+5)=-20z-2(-z-8)

We move all terms to the left:

-7(3z+5)-(-20z-2(-z-8))=0

We add all the numbers together, and all the variables

-7(3z+5)-(-20z-2(-1z-8))=0

We multiply parentheses

-21z-(-20z-2(-1z-8))-35=0



We calculate terms in parentheses: -(-20z-2(-1z-8)), so:

-20z-2(-1z-8)

We multiply parentheses

-20z+2z+16

We add all the numbers together, and all the variables

-18z+16

Back to the equation:

-(-18z+16)



We get rid of parentheses

-21z+18z-16-35=0

We add all the numbers together, and all the variables

-3z-51=0

We move all terms containing z to the left, all other terms to the right

-3z=51

z=51/-3

z=-17

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