-7(3z-12)=63

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Solution for -7(3z-12)=63 equation: 



-7(3z-12)=63

We move all terms to the left:

-7(3z-12)-(63)=0

We multiply parentheses

-21z+84-63=0

We add all the numbers together, and all the variables

-21z+21=0

We move all terms containing z to the left, all other terms to the right

-21z=-21

z=-21/-21

z=1

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