-7(4b+1)+(29b-1)=0

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Solution for -7(4b+1)+(29b-1)=0 equation:


Simplifying
-7(4b + 1) + (29b + -1) = 0

Reorder the terms:
-7(1 + 4b) + (29b + -1) = 0
(1 * -7 + 4b * -7) + (29b + -1) = 0
(-7 + -28b) + (29b + -1) = 0

Reorder the terms:
-7 + -28b + (-1 + 29b) = 0

Remove parenthesis around (-1 + 29b)
-7 + -28b + -1 + 29b = 0

Reorder the terms:
-7 + -1 + -28b + 29b = 0

Combine like terms: -7 + -1 = -8
-8 + -28b + 29b = 0

Combine like terms: -28b + 29b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8

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