-7(4b+1)+(29b-3)=0

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Solution for -7(4b+1)+(29b-3)=0 equation:


Simplifying
-7(4b + 1) + (29b + -3) = 0

Reorder the terms:
-7(1 + 4b) + (29b + -3) = 0
(1 * -7 + 4b * -7) + (29b + -3) = 0
(-7 + -28b) + (29b + -3) = 0

Reorder the terms:
-7 + -28b + (-3 + 29b) = 0

Remove parenthesis around (-3 + 29b)
-7 + -28b + -3 + 29b = 0

Reorder the terms:
-7 + -3 + -28b + 29b = 0

Combine like terms: -7 + -3 = -10
-10 + -28b + 29b = 0

Combine like terms: -28b + 29b = 1b
-10 + 1b = 0

Solving
-10 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = 0 + 10
1b = 0 + 10

Combine like terms: 0 + 10 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10

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