-7(4b+1)+(29b-5)=0

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Solution for -7(4b+1)+(29b-5)=0 equation:


Simplifying
-7(4b + 1) + (29b + -5) = 0

Reorder the terms:
-7(1 + 4b) + (29b + -5) = 0
(1 * -7 + 4b * -7) + (29b + -5) = 0
(-7 + -28b) + (29b + -5) = 0

Reorder the terms:
-7 + -28b + (-5 + 29b) = 0

Remove parenthesis around (-5 + 29b)
-7 + -28b + -5 + 29b = 0

Reorder the terms:
-7 + -5 + -28b + 29b = 0

Combine like terms: -7 + -5 = -12
-12 + -28b + 29b = 0

Combine like terms: -28b + 29b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12

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