-7(4b+2)+(29b-2)=0

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Solution for -7(4b+2)+(29b-2)=0 equation:


Simplifying
-7(4b + 2) + (29b + -2) = 0

Reorder the terms:
-7(2 + 4b) + (29b + -2) = 0
(2 * -7 + 4b * -7) + (29b + -2) = 0
(-14 + -28b) + (29b + -2) = 0

Reorder the terms:
-14 + -28b + (-2 + 29b) = 0

Remove parenthesis around (-2 + 29b)
-14 + -28b + -2 + 29b = 0

Reorder the terms:
-14 + -2 + -28b + 29b = 0

Combine like terms: -14 + -2 = -16
-16 + -28b + 29b = 0

Combine like terms: -28b + 29b = 1b
-16 + 1b = 0

Solving
-16 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 1b = 0 + 16
1b = 0 + 16

Combine like terms: 0 + 16 = 16
1b = 16

Divide each side by '1'.
b = 16

Simplifying
b = 16

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