-7(4b+3)+(29b-5)=0

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Solution for -7(4b+3)+(29b-5)=0 equation:


Simplifying
-7(4b + 3) + (29b + -5) = 0

Reorder the terms:
-7(3 + 4b) + (29b + -5) = 0
(3 * -7 + 4b * -7) + (29b + -5) = 0
(-21 + -28b) + (29b + -5) = 0

Reorder the terms:
-21 + -28b + (-5 + 29b) = 0

Remove parenthesis around (-5 + 29b)
-21 + -28b + -5 + 29b = 0

Reorder the terms:
-21 + -5 + -28b + 29b = 0

Combine like terms: -21 + -5 = -26
-26 + -28b + 29b = 0

Combine like terms: -28b + 29b = 1b
-26 + 1b = 0

Solving
-26 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '26' to each side of the equation.
-26 + 26 + 1b = 0 + 26

Combine like terms: -26 + 26 = 0
0 + 1b = 0 + 26
1b = 0 + 26

Combine like terms: 0 + 26 = 26
1b = 26

Divide each side by '1'.
b = 26

Simplifying
b = 26

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