-7(5x-4)-7(8x-3)=10(2x+3)-9(8x+5)

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Solution for -7(5x-4)-7(8x-3)=10(2x+3)-9(8x+5) equation:



-7(5x-4)-7(8x-3)=10(2x+3)-9(8x+5)
We move all terms to the left:
-7(5x-4)-7(8x-3)-(10(2x+3)-9(8x+5))=0
We multiply parentheses
-35x-56x-(10(2x+3)-9(8x+5))+28+21=0
We calculate terms in parentheses: -(10(2x+3)-9(8x+5)), so:
10(2x+3)-9(8x+5)
We multiply parentheses
20x-72x+30-45
We add all the numbers together, and all the variables
-52x-15
Back to the equation:
-(-52x-15)
We add all the numbers together, and all the variables
-91x-(-52x-15)+49=0
We get rid of parentheses
-91x+52x+15+49=0
We add all the numbers together, and all the variables
-39x+64=0
We move all terms containing x to the left, all other terms to the right
-39x=-64
x=-64/-39
x=1+25/39

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