-7(a-7)+1=3a+10(5-10a)

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Solution for -7(a-7)+1=3a+10(5-10a) equation: 



-7(a-7)+1=3a+10(5-10a)

We move all terms to the left:

-7(a-7)+1-(3a+10(5-10a))=0

We add all the numbers together, and all the variables

-7(a-7)-(3a+10(-10a+5))+1=0

We multiply parentheses

-7a-(3a+10(-10a+5))+49+1=0



We calculate terms in parentheses: -(3a+10(-10a+5)), so:

3a+10(-10a+5)

We multiply parentheses

3a-100a+50

We add all the numbers together, and all the variables

-97a+50

Back to the equation:

-(-97a+50)



We add all the numbers together, and all the variables

-7a-(-97a+50)+50=0

We get rid of parentheses

-7a+97a-50+50=0

We add all the numbers together, and all the variables

90a=0

a=0/90

a=0

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