-7(b+1)=5(b-2)

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Solution for -7(b+1)=5(b-2) equation:


Simplifying
-7(b + 1) = 5(b + -2)

Reorder the terms:
-7(1 + b) = 5(b + -2)
(1 * -7 + b * -7) = 5(b + -2)
(-7 + -7b) = 5(b + -2)

Reorder the terms:
-7 + -7b = 5(-2 + b)
-7 + -7b = (-2 * 5 + b * 5)
-7 + -7b = (-10 + 5b)

Solving
-7 + -7b = -10 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
-7 + -7b + -5b = -10 + 5b + -5b

Combine like terms: -7b + -5b = -12b
-7 + -12b = -10 + 5b + -5b

Combine like terms: 5b + -5b = 0
-7 + -12b = -10 + 0
-7 + -12b = -10

Add '7' to each side of the equation.
-7 + 7 + -12b = -10 + 7

Combine like terms: -7 + 7 = 0
0 + -12b = -10 + 7
-12b = -10 + 7

Combine like terms: -10 + 7 = -3
-12b = -3

Divide each side by '-12'.
b = 0.25

Simplifying
b = 0.25

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