-7(b-2)-4(6+b)=b-7+2/7b

Solution for -7(b-2)-4(6+b)=b-7+2/7b equation:

-7(b-2)-4(6+b)=b-7+2/7b

We move all terms to the left:

-7(b-2)-4(6+b)-(b-7+2/7b)=0


Domain of the equation: 7b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-7(b-2)-4(b+6)-(b+2/7b-7)=0

We multiply parentheses

-7b-4b-(b+2/7b-7)+14-24=0

We get rid of parentheses

-7b-4b-b-2/7b+7+14-24=0

We multiply all the terms by the denominator


-7b*7b-4b*7b-b*7b+7*7b+14*7b-24*7b-2=0

Wy multiply elements

-49b^2-28b^2-7b^2+49b+98b-168b-2=0

We add all the numbers together, and all the variables

-84b^2-21b-2=0

a = -84; b = -21; c = -2;
Δ = b2-4ac
Δ = -212-4·(-84)·(-2)
Δ = -231
Delta is less than zero, so there is no solution for the equation