-7(d-2)=5(-d+2)-2d+4

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Solution for -7(d-2)=5(-d+2)-2d+4 equation: 



-7(d-2)=5(-d+2)-2d+4

We move all terms to the left:

-7(d-2)-(5(-d+2)-2d+4)=0

We add all the numbers together, and all the variables

-7(d-2)-(5(-1d+2)-2d+4)=0

We multiply parentheses

-7d-(5(-1d+2)-2d+4)+14=0



We calculate terms in parentheses: -(5(-1d+2)-2d+4), so:

5(-1d+2)-2d+4

We add all the numbers together, and all the variables

-2d+5(-1d+2)+4

We multiply parentheses

-2d-5d+10+4

We add all the numbers together, and all the variables

-7d+14

Back to the equation:

-(-7d+14)



We get rid of parentheses

-7d+7d-14+14=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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