-7(k+2)-k-5=-8(k+4)+13

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Solution for -7(k+2)-k-5=-8(k+4)+13 equation: 



-7(k+2)-k-5=-8(k+4)+13

We move all terms to the left:

-7(k+2)-k-5-(-8(k+4)+13)=0

We add all the numbers together, and all the variables

-1k-7(k+2)-(-8(k+4)+13)-5=0

We multiply parentheses

-1k-7k-(-8(k+4)+13)-14-5=0



We calculate terms in parentheses: -(-8(k+4)+13), so:

-8(k+4)+13

We multiply parentheses

-8k-32+13

We add all the numbers together, and all the variables

-8k-19

Back to the equation:

-(-8k-19)



We add all the numbers together, and all the variables

-8k-(-8k-19)-19=0

We get rid of parentheses

-8k+8k+19-19=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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