-7(k+9)=3(k-5)-14k

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Solution for -7(k+9)=3(k-5)-14k equation: 



-7(k+9)=3(k-5)-14k

We move all terms to the left:

-7(k+9)-(3(k-5)-14k)=0

We multiply parentheses

-7k-(3(k-5)-14k)-63=0



We calculate terms in parentheses: -(3(k-5)-14k), so:

3(k-5)-14k

We add all the numbers together, and all the variables

-14k+3(k-5)

We multiply parentheses

-14k+3k-15

We add all the numbers together, and all the variables

-11k-15

Back to the equation:

-(-11k-15)



We get rid of parentheses

-7k+11k+15-63=0

We add all the numbers together, and all the variables

4k-48=0

We move all terms containing k to the left, all other terms to the right

4k=48

k=48/4

k=12

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