-7(k-3)+2=8(k-2)-2k

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Solution for -7(k-3)+2=8(k-2)-2k equation: 



-7(k-3)+2=8(k-2)-2k

We move all terms to the left:

-7(k-3)+2-(8(k-2)-2k)=0

We multiply parentheses

-7k-(8(k-2)-2k)+21+2=0



We calculate terms in parentheses: -(8(k-2)-2k), so:

8(k-2)-2k

We add all the numbers together, and all the variables

-2k+8(k-2)

We multiply parentheses

-2k+8k-16

We add all the numbers together, and all the variables

6k-16

Back to the equation:

-(6k-16)



We add all the numbers together, and all the variables

-7k-(6k-16)+23=0

We get rid of parentheses

-7k-6k+16+23=0

We add all the numbers together, and all the variables

-13k+39=0

We move all terms containing k to the left, all other terms to the right

-13k=-39

k=-39/-13

k=+3

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