-7(n+1)+n=-(4n-2)+7n

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Solution for -7(n+1)+n=-(4n-2)+7n equation: 



-7(n+1)+n=-(4n-2)+7n

We move all terms to the left:

-7(n+1)+n-(-(4n-2)+7n)=0

We add all the numbers together, and all the variables

n-7(n+1)-(-(4n-2)+7n)=0

We multiply parentheses

n-7n-(-(4n-2)+7n)-7=0



We calculate terms in parentheses: -(-(4n-2)+7n), so:

-(4n-2)+7n

We add all the numbers together, and all the variables

7n-(4n-2)

We get rid of parentheses

7n-4n+2

We add all the numbers together, and all the variables

3n+2

Back to the equation:

-(3n+2)



We add all the numbers together, and all the variables

-6n-(3n+2)-7=0

We get rid of parentheses

-6n-3n-2-7=0

We add all the numbers together, and all the variables

-9n-9=0

We move all terms containing n to the left, all other terms to the right

-9n=9

n=9/-9

n=-1

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