-7(r+5)+3r=2(5-2r)

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Solution for -7(r+5)+3r=2(5-2r) equation: 



-7(r+5)+3r=2(5-2r)

We move all terms to the left:

-7(r+5)+3r-(2(5-2r))=0

We add all the numbers together, and all the variables

-7(r+5)+3r-(2(-2r+5))=0

We add all the numbers together, and all the variables

3r-7(r+5)-(2(-2r+5))=0

We multiply parentheses

3r-7r-(2(-2r+5))-35=0



We calculate terms in parentheses: -(2(-2r+5)), so:

2(-2r+5)

We multiply parentheses

-4r+10

Back to the equation:

-(-4r+10)



We add all the numbers together, and all the variables

-4r-(-4r+10)-35=0

We get rid of parentheses

-4r+4r-10-35=0

We add all the numbers together, and all the variables

-45!=0

There is no solution for this equation

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