-7(t-6)-(t+3)=6

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Solution for -7(t-6)-(t+3)=6 equation: 



-7(t-6)-(t+3)=6

We move all terms to the left:

-7(t-6)-(t+3)-(6)=0

We multiply parentheses

-7t-(t+3)+42-6=0

We get rid of parentheses

-7t-t-3+42-6=0

We add all the numbers together, and all the variables

-8t+33=0

We move all terms containing t to the left, all other terms to the right

-8t=-33

t=-33/-8

t=4+1/8

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