-7(u+1)=2u-6+2(3u+4)

Solution for -7(u+1)=2u-6+2(3u+4) equation:

-7(u+1)=2u-6+2(3u+4)

We move all terms to the left:

-7(u+1)-(2u-6+2(3u+4))=0

We multiply parentheses

-7u-(2u-6+2(3u+4))-7=0


We calculate terms in parentheses: -(2u-6+2(3u+4)), so:

2u-6+2(3u+4)

determiningTheFunctionDomain
2u+2(3u+4)-6

We multiply parentheses

2u+6u+8-6

We add all the numbers together, and all the variables

8u+2

Back to the equation:

-(8u+2)


We get rid of parentheses

-7u-8u-2-7=0

We add all the numbers together, and all the variables

-15u-9=0

We move all terms containing u to the left, all other terms to the right

-15u=9

u=9/-15

u=-3/5