-7(u+2)=3u-8+2(2u+5)

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Solution for -7(u+2)=3u-8+2(2u+5) equation: 



-7(u+2)=3u-8+2(2u+5)

We move all terms to the left:

-7(u+2)-(3u-8+2(2u+5))=0

We multiply parentheses

-7u-(3u-8+2(2u+5))-14=0



We calculate terms in parentheses: -(3u-8+2(2u+5)), so:

3u-8+2(2u+5)

determiningTheFunctionDomain
3u+2(2u+5)-8

We multiply parentheses

3u+4u+10-8

We add all the numbers together, and all the variables

7u+2

Back to the equation:

-(7u+2)



We get rid of parentheses

-7u-7u-2-14=0

We add all the numbers together, and all the variables

-14u-16=0

We move all terms containing u to the left, all other terms to the right

-14u=16

u=16/-14

u=-1+1/7

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