-7(v+1)=3v-1+2(4v+5)

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Solution for -7(v+1)=3v-1+2(4v+5) equation: 



-7(v+1)=3v-1+2(4v+5)

We move all terms to the left:

-7(v+1)-(3v-1+2(4v+5))=0

We multiply parentheses

-7v-(3v-1+2(4v+5))-7=0



We calculate terms in parentheses: -(3v-1+2(4v+5)), so:

3v-1+2(4v+5)

determiningTheFunctionDomain
3v+2(4v+5)-1

We multiply parentheses

3v+8v+10-1

We add all the numbers together, and all the variables

11v+9

Back to the equation:

-(11v+9)



We get rid of parentheses

-7v-11v-9-7=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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