-7(v+1)=3v-9+2(2v+3)

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Solution for -7(v+1)=3v-9+2(2v+3) equation: 



-7(v+1)=3v-9+2(2v+3)

We move all terms to the left:

-7(v+1)-(3v-9+2(2v+3))=0

We multiply parentheses

-7v-(3v-9+2(2v+3))-7=0



We calculate terms in parentheses: -(3v-9+2(2v+3)), so:

3v-9+2(2v+3)

determiningTheFunctionDomain
3v+2(2v+3)-9

We multiply parentheses

3v+4v+6-9

We add all the numbers together, and all the variables

7v-3

Back to the equation:

-(7v-3)



We get rid of parentheses

-7v-7v+3-7=0

We add all the numbers together, and all the variables

-14v-4=0

We move all terms containing v to the left, all other terms to the right

-14v=4

v=4/-14

v=-2/7

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