-7(v+2)=5v-8+2(3v+5)

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Solution for -7(v+2)=5v-8+2(3v+5) equation: 



-7(v+2)=5v-8+2(3v+5)

We move all terms to the left:

-7(v+2)-(5v-8+2(3v+5))=0

We multiply parentheses

-7v-(5v-8+2(3v+5))-14=0



We calculate terms in parentheses: -(5v-8+2(3v+5)), so:

5v-8+2(3v+5)

determiningTheFunctionDomain
5v+2(3v+5)-8

We multiply parentheses

5v+6v+10-8

We add all the numbers together, and all the variables

11v+2

Back to the equation:

-(11v+2)



We get rid of parentheses

-7v-11v-2-14=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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