-7(x+1)+4x-(x+2)=3(5-x)+12

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Solution for -7(x+1)+4x-(x+2)=3(5-x)+12 equation: 



-7(x+1)+4x-(x+2)=3(5-x)+12

We move all terms to the left:

-7(x+1)+4x-(x+2)-(3(5-x)+12)=0

We add all the numbers together, and all the variables

-7(x+1)+4x-(x+2)-(3(-1x+5)+12)=0

We add all the numbers together, and all the variables

4x-7(x+1)-(x+2)-(3(-1x+5)+12)=0

We multiply parentheses

4x-7x-(x+2)-(3(-1x+5)+12)-7=0

We get rid of parentheses

4x-7x-x-(3(-1x+5)+12)-2-7=0



We calculate terms in parentheses: -(3(-1x+5)+12), so:

3(-1x+5)+12

We multiply parentheses

-3x+15+12

We add all the numbers together, and all the variables

-3x+27

Back to the equation:

-(-3x+27)



We add all the numbers together, and all the variables

-4x-(-3x+27)-9=0

We get rid of parentheses

-4x+3x-27-9=0

We add all the numbers together, and all the variables

-1x-36=0

We move all terms containing x to the left, all other terms to the right

-x=36

x=36/-1

x=-36

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