-7(x+11)+3=2(x-4)-12

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Solution for -7(x+11)+3=2(x-4)-12 equation:



-7(x+11)+3=2(x-4)-12
We move all terms to the left:
-7(x+11)+3-(2(x-4)-12)=0
We multiply parentheses
-7x-(2(x-4)-12)-77+3=0
We calculate terms in parentheses: -(2(x-4)-12), so:
2(x-4)-12
We multiply parentheses
2x-8-12
We add all the numbers together, and all the variables
2x-20
Back to the equation:
-(2x-20)
We add all the numbers together, and all the variables
-7x-(2x-20)-74=0
We get rid of parentheses
-7x-2x+20-74=0
We add all the numbers together, and all the variables
-9x-54=0
We move all terms containing x to the left, all other terms to the right
-9x=54
x=54/-9
x=-6

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