-7(x+11)+3=2(x-4)-12

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Solution for -7(x+11)+3=2(x-4)-12 equation: 



-7(x+11)+3=2(x-4)-12

We move all terms to the left:

-7(x+11)+3-(2(x-4)-12)=0

We multiply parentheses

-7x-(2(x-4)-12)-77+3=0



We calculate terms in parentheses: -(2(x-4)-12), so:

2(x-4)-12

We multiply parentheses

2x-8-12

We add all the numbers together, and all the variables

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

-7x-(2x-20)-74=0

We get rid of parentheses

-7x-2x+20-74=0

We add all the numbers together, and all the variables

-9x-54=0

We move all terms containing x to the left, all other terms to the right

-9x=54

x=54/-9

x=-6

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