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-7(x+2)=3x-5+3(2x+3)
We move all terms to the left:
-7(x+2)-(3x-5+3(2x+3))=0
We multiply parentheses
-7x-(3x-5+3(2x+3))-14=0
We calculate terms in parentheses: -(3x-5+3(2x+3)), so:We get rid of parentheses
3x-5+3(2x+3)
determiningTheFunctionDomain 3x+3(2x+3)-5
We multiply parentheses
3x+6x+9-5
We add all the numbers together, and all the variables
9x+4
Back to the equation:
-(9x+4)
-7x-9x-4-14=0
We add all the numbers together, and all the variables
-16x-18=0
We move all terms containing x to the left, all other terms to the right
-16x=18
x=18/-16
x=-1+1/8
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