-7(x-2)+4x=29-3(1-x)

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Solution for -7(x-2)+4x=29-3(1-x) equation: 



-7(x-2)+4x=29-3(1-x)

We move all terms to the left:

-7(x-2)+4x-(29-3(1-x))=0

We add all the numbers together, and all the variables

-7(x-2)+4x-(29-3(-1x+1))=0

We add all the numbers together, and all the variables

4x-7(x-2)-(29-3(-1x+1))=0

We multiply parentheses

4x-7x-(29-3(-1x+1))+14=0



We calculate terms in parentheses: -(29-3(-1x+1)), so:

29-3(-1x+1)

determiningTheFunctionDomain
-3(-1x+1)+29

We multiply parentheses

3x-3+29

We add all the numbers together, and all the variables

3x+26

Back to the equation:

-(3x+26)



We add all the numbers together, and all the variables

-3x-(3x+26)+14=0

We get rid of parentheses

-3x-3x-26+14=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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