-7(x-2)=3(x-3)-10x+23

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Solution for -7(x-2)=3(x-3)-10x+23 equation: 



-7(x-2)=3(x-3)-10x+23

We move all terms to the left:

-7(x-2)-(3(x-3)-10x+23)=0

We multiply parentheses

-7x-(3(x-3)-10x+23)+14=0



We calculate terms in parentheses: -(3(x-3)-10x+23), so:

3(x-3)-10x+23

We add all the numbers together, and all the variables

-10x+3(x-3)+23

We multiply parentheses

-10x+3x-9+23

We add all the numbers together, and all the variables

-7x+14

Back to the equation:

-(-7x+14)



We get rid of parentheses

-7x+7x-14+14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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