-7(x-5)+3x-2(x+8)=8+4x-7x+4(2x-8)

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Solution for -7(x-5)+3x-2(x+8)=8+4x-7x+4(2x-8) equation: 



-7(x-5)+3x-2(x+8)=8+4x-7x+4(2x-8)

We move all terms to the left:

-7(x-5)+3x-2(x+8)-(8+4x-7x+4(2x-8))=0

We add all the numbers together, and all the variables

3x-7(x-5)-2(x+8)-(8+4x-7x+4(2x-8))=0

We multiply parentheses

3x-7x-2x-(8+4x-7x+4(2x-8))+35-16=0



We calculate terms in parentheses: -(8+4x-7x+4(2x-8)), so:

8+4x-7x+4(2x-8)

determiningTheFunctionDomain
4x-7x+4(2x-8)+8

We add all the numbers together, and all the variables

-3x+4(2x-8)+8

We multiply parentheses

-3x+8x-32+8

We add all the numbers together, and all the variables

5x-24

Back to the equation:

-(5x-24)



We add all the numbers together, and all the variables

-6x-(5x-24)+19=0

We get rid of parentheses

-6x-5x+24+19=0

We add all the numbers together, and all the variables

-11x+43=0

We move all terms containing x to the left, all other terms to the right

-11x=-43

x=-43/-11

x=3+10/11

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