-7(y+1)+3(4y-7)=4(y-4)+11

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Solution for -7(y+1)+3(4y-7)=4(y-4)+11 equation: 



-7(y+1)+3(4y-7)=4(y-4)+11

We move all terms to the left:

-7(y+1)+3(4y-7)-(4(y-4)+11)=0

We multiply parentheses

-7y+12y-(4(y-4)+11)-7-21=0



We calculate terms in parentheses: -(4(y-4)+11), so:

4(y-4)+11

We multiply parentheses

4y-16+11

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)



We add all the numbers together, and all the variables

5y-(4y-5)-28=0

We get rid of parentheses

5y-4y+5-28=0

We add all the numbers together, and all the variables

y-23=0

We move all terms containing y to the left, all other terms to the right

y=23

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